若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 16:22:31
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则
A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z=0
zx/﹙z+2x﹚=3③
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
对等式①,②,③取倒数可得
2/x + 1/y = 1 (1)
2/y + 1/z = 1/2 (2)
2/z + 1/x = 1/3 (3)
(1)* 4 - (2)*2 + (3)可得9/x = 10/3,x=27/10,
把x=27/10带入(1)可得y= 27/7,
把x=27/10带入(3)可得z= -54.
所以10x+7y+z=0,答案为D.
你是不是少东西了 那个③等于多少啊
若实数XYZ满足方程组 XY除以(X+2Y)=1 YZ除以(Y+2Z)=2 ZX除以(Z+2X) 则有
若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则若实数x,y,z满足方程组 xy/﹙x+2y﹚=1① yz/﹙y+2z﹚=2② zx/﹙z+2x﹚③ 则A.x+2y+3z=0 B.7x+5y+2z=0 C.9x+6y+sz=0 D.10x+7y+z
若实数x,y,z满足x+y+z=5,xy+yz+xz=3,求z的最大值
若x y z满足方程组xy+z=94,x+yz=95求xyz=?
若实数xy满足x-y+1
已知实数x,y,z,满足那么x+y=6,z^2=xy-9,求(x+y)^z
:设X,Y,Z是正实数,满足XY+Z=(X+Z)(Y+Z),则XYZ的最大值是
数学竞赛题:若实数x,y满足方程组xy+x+y+7=0,3x+3y=9+2xy,则x2y+xy2=?
已知实数x,y,z满足x=6-y,z^2=xy-9,求证:x=y
已知实数x,y,z满足x=6-y,z²=xy-9,求证:x=y
已知实数x,y,z满足x+y=6,z的平方=xy-9,求证x=y
若实数xyz满足x等于4—y,z平方等于xy—4 求证x等于y
若实数xyz满足x=6-y,z^2=xy-9.求证x=y快
若实数x、y、z满足x^2+2y^2+z^2+5小于或等于2xy-2y+4z,求xyz的值
若实数x、y、z满足x^2+2y^2+z^2+5小于或等于2xy-2y+4z,求xyz的值
实数x,y,z满足x+y+z=5,xy+yz+zx=3,求z的最大值
已知,实数x,y,z满足x+y+z=0,xy+yz+zx=-3,求z的最大值
若实数XYZ满足方程组 XY除以(X+2Y)=1 YZ除以(Y+2Z)=2 ZX除以(Z+2X) 则有(A) X+2Y+3Z=0 (B) 7X+5Y+2Z=0 (C) 9X+6Y+3Z=0 (d) 10X+7y+Z=0选哪一个?急用!ZX除以(Z+2X)=3