:3x²-[5x-(1/2x-3)+2x²]

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:3x²-[5x-(1/2x-3)+2x²]
:3x²-[5x-(1/2x-3)+2x²]

:3x²-[5x-(1/2x-3)+2x²]
3x²-[5x-(1/2x-3)+2x²]
=3x²-[5x-1/2x+3+2x²]
=3x²-[9/2x+3+2x²]
=3x²-9/2x-3-2x²
=3x²-2x²-9/2x-3
=x²-9/2x-3

3x²-[5x-(1/2x-3)+2x²]
=3x²-(5x-1/2x+3+2x²)
=3x²-5x+1/2x-3-2x²
=x²-(9/2)x-3

x²-9/2x-3

xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 两个初升高衔接教材的数学题.①(x²+x+1)(x²+x+2)-12=(x²+x+1)(x²+x+1+1)-12=(x²+x+1)²+(x²+x+1)-12=(x²+x-3)(x²+x+5)[十字相乘法]②(x²+x)²-8(x²+x)+12=(x²+x-2)(x²+x-6)[ 混合运算6x+2x²-3x+x²+1其中x=-5 1/X²+3X+2 +1/X²+5X+6 +1/X²+7X+12 +1/X²+9X+20 (x²-4分之x²+x+1)²÷(x三次方-3x²+2x÷x三次方)²×(x÷x+2)² , x²-9/x²+2x-3乘3x²-x-2/x²-5x+6, 化简x(x-1)+2x(x+1)-3x(2x-5)我是这一算的,化简x(x-1)+2x(x+1)-3x(2x-5)=x²-x+2x²+2x-6x²+15x=x+2x²-6x²+15x=18x+2x²-6x²=12x²-6x²可以相减吗,还是我算的不对了? 已知关于x的多项式(2mx²-x²+3x+1)-(5x²-4y²+3x)不含x²项 1.(3x²+10x²+13x-27)/(x²+2x-3)2.(2x²+x³-2)/(x²-1)3.已知A=(3x)²-21x³-2x²+11x-2 B=3x³-5x²-4x+1求a²/b² 在实数范围内分解因式 x²+x-1 x²-2x-6 2x²+8x-7 x²-5xy+3y² -2x²-3x+6 4x& 在线求助完全平方公式因式分解(1)-a²-1+2a(2)2x²y-x²-xy²(3)4x²-20x+25(4)(x²+1)²-4x²(5)(2x-y)²-2(2x-y)+1(6)(x+y)²-2(x²-y²)+(x-y)² 试说明不论X取何值代数式(x²+5x²+4x-1)-(-x²-3x+2x²-3)+(8-7x-6x²+x²)的 1.x²-2x-3 2.x²-5x-6 3.x²-9x-10 4.x²-9x-10 5.x²-2x-8 6.x²+2x-8 7.x²-x-12 8.x²+x-12 9.x²+6x-16 10.x²-14x-32 11.x²+7x-18 xy²/(x²y) - y×x²/(x²+x)=(x²-3x)/(x²-5x×2x) - 10/(x²-6x+9)=2a/(a²-4) - 1/(a-2)=2/(1-a ) - 1/(a-1)=x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 解下列方程!就三道!解下列方程.1、x/x-2 - 1-x²/x²-5x = 2x/x-3(x/x-2 - 1-x²不是一起的!)2、5x/x²+x-6 - 5-2x/x²-x-12=7x-10/x²-6x+8(5x/x²+x-6 - 5-2x不是一起的!)3、x-4/x-5 + x-8/x-9=x-7/x- 化简~(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)注意了!是三个分式!(x²+3x+9)/(x²-27)+(6x)/(9x-x²)-(x-1)/(6+2x) 整式乘法..1.3xy(x²y-xy²+xy)-xy²(2x²-xy+2x)2.(x-1)(x²-4x+3)-x(x²-5x+2) :3x²-[5x-(1/2x-3)+2x²]