求解:已知:x2-x-1=0,x5-5x-1=?
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求解:已知:x2-x-1=0,x5-5x-1=?
求解:已知:x2-x-1=0,x5-5x-1=?
求解:已知:x2-x-1=0,x5-5x-1=?
2,可采用降次的办法,X2=X+1代入X5-5X-1=X3(X+1)-5X-1=X4+X3-5X-1同理代入可得结果为2
(根号5-1)/2 或者(根号5+1)/2
求解:已知:x2-x-1=0,x5-5x-1=?
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