若tanα=m 则sin(-5π-α)cos(3x+α)=
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若tanα=m 则sin(-5π-α)cos(3x+α)=
若tanα=m 则sin(-5π-α)cos(3x+α)=
若tanα=m 则sin(-5π-α)cos(3x+α)=
sin(-5π-α)cos(3π+α)
=sina*(-cosa)
=-sinacosa
=-sinacosa/(sin^2a+cos^2a) 分子分母同时除以 cos^2a
=-tana/(1+tan^2a) tanα=m
=-m/(1+m^2)
若tanα=m 则sin(-5π-α)cos(3x+α)=
M=sinα×tan(α/2)+cosα,N=tanπ/8(tanπ/8+2),则M与N的大小关系是A.M>N B.M=N C.M
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