tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/09 10:06:40
tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)
=-sin(α)-cos(α) / -sin(α)+cos(α)
= -tan(α)-1 / -tan(α)+1
=(-m-1)/(-m+1)
=(m+1)/(m-1)
tanα=m,则sin(α+3π)+cos(π+α)/sin(-α)-cos(π+α)等于?
若tanα=m 则sin(-5π-α)cos(3x+α)=
若tanα-sinα=m,tanα+sinα=n,则cosα等于?
已知sinα=m-3/m+5,cosα=4-2m/m+5,若α∈(π/2,π),则tanα/2的值
若tan(π+α)=m,3π/2<α<2π,则sin(π-α)=
M=sinα×tan(α/2)+cosα,N=tanπ/8(tanπ/8+2),则M与N的大小关系是A.M>N B.M=N C.M
设tan(5π+α)=m,则sin(α-3π)+cos(π-α)/sin(-α)-cos(π+α)的值为
已知α,β∈(0,π/2),且2tanα+3sinβ=7,tanα-6sinβ=1,则sinα=
已知tanα=m求sinα cosα
三角函数(求详细过程)(1)、根号下1-sinα/1+sinα=sinα-1/cosα,则x是?象限角(2)、tanα=m(m不等于0)且sinα=4-2m/m+5,求m和tanα(3)、若sinα*cosα=1/2,求tanα+cosα/sinα(4)、已知:0
tanα=3 则sinαcosα=?
tanαtan2α/(tan2α+tanα)=sin2α证明tanatan2a/(tan2a-tana)+根号3(sin^2a-co^2)=2sin(2a-派/3) 证明下
tanα=根号3/3,则sinα等于
已知sinβ=msin(2α+β),切tan(α+β) anα=3,则实数m的值为
证明三角恒等式tanαsinα/(tanα-sinα)=(tanα+sinα)/tanαsinα
证明:(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)
证明:(tanα*sinα)/(tanα-sinα)=(tanα+sinα)/(tanα*sinα)
求证(tanα·sinα)/(tanα-sinα)=(tanα+sinα)/(tanα·sinα)