若log(27)12=1/a,则log(6)16=?括号内的为底数,括号外的为真数,请写明过程.

27-1/ 若a>0,b>0,a*b>1,log(1/2)[a]=ln2,则log(a)[b]与log(1/2)[a]的关系是：（）?(A)log(a)b< log(1/2)[a](B)log(a)b= log(1/2)[a](C)log(a)b>log(1/2)[a](D)log(a)b与log(1/2)[a] 无法比较大小我做到一半就做不下去了：a=(1/2)^(ln2)log 若log(2)3=(1-a)/a则log(3)12RT求详解 已知Log( 12)27=a ,求Log( 6 ) 16 若| log a 1/4 |=log a 1/4 ,| log b a |=-log b a 则 a b满足什么条件0＜a＜1 b＞1log旁边的a在下面 若log(27)12=1/a,则log(6)16=?括号内的为底数,括号外的为真数,请写明过程. 1、若lg2=a,lg3=b,则lg√15=?（用a、b表达）2、若log(15)(5)=m,则log(15)(3)=(用m表示)3、log(2)(3)*log(3)(4)*log(4)(5)*log(5)(6)*log(6)(7)*log(7)(8）=?4、设log(3)(2)=log(2)(3^x),x=?这个对数函数我学的很不好,所以希望过 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 关于数学对数的换底公式推论的问题已知 log(2)(3) = a,log(3(7)=b,用a,b表示log(42)(56)因为log(2)(3)=a,则1/a=log(3)(2),又∵log(3)(7)=b,∴log(42)(56)=log(3)(56)/log(3)(42)=log(3)(7)+3·log(3)(2)/log(3)(7)+log(3)(2)+1=ab+3/ab+b+1 设a>b>1,log(a)b+log(b)a=10/3,则log(a)b-log(b)a= 请问为什么1/log(a)k=log(k)a? 对数的运算问题-log a 1/x=-(log a 1-log a x)=log a x 求证 log(a)^(b)=1/log(b)^(a)求证 log(a)^(b)=1/log(b)^(a) 已知log(a)x=1,log(b)x=2,log(c)x=4,则log(abc)x=? 已知log(8)27=a,求log(6)16 log(2)3=a,则log(6)4=（ 可以说log a x +log a y=log a （1）已知lg3=0.4771, lgx=-3.5229,则x=? (2) 若log(3)2=a,用a表示代数式log(2)12=? 幂指对函数log(12)27=a,用a表示log(6)16