作业帮lim 1(x/(x-1)-1/(lnx))
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/08 09:29:06
lim 1(x/(x-1)-1/(lnx))
lim 1(x/(x-1)-1/(lnx))
lim 1(x/(x-1)-1/(lnx))
lim (x→1) (x/(x-1)-1/(lnx))
=lim (x→1) [xlnx-(x-1)]/[(x-1)(lnx)] (0/0)
=lim (x→1) (lnx+1-1)]/[lnx+1-1/x]
=lim (x→1) xlnx/(xlnx+x-1) (0/0)
=lim (x→1) (lnx+1)/(lnx+1+1)
=1/2
lim(lnx)-1/(x-e)
lim 1(x/(x-1)-1/(lnx))
lim(x→1)((1-x)/lnx)
lim x趋向1 x-x^x/(1-x+lnx)
lim→0+ lnx ln(1+X)
数学极限题Lim x^x-x/(1+lnx-x)Lim x^x-x/(1+lnx-x)x→1
lim(x/x-1-1/lnx)x趋于1
lim(x趋向于1)[x/(1-x)-1/lnx]
求lim(X/X-1-1/lnx) x－1
求极限lim(x->1)(x-1/x)/lnx
lim x->无限大 (1+1/2x) ^ 3x+lnx
lim(x→∞)x[ln(x-1)-lnx]
x趋向0+时求lim(x^x-1)*lnx
极限lim[(a^x-a*lnx)/(b^x-b*lnx)]^(1/x^2),x->0
lim(x趋于1)1/lnx-1/x-1=
lim（x-无穷）(1/1+x)^1/lnx
用洛必达法则计算：lim x→1(lnx/x-1)
lim x趋向1 lnx/(x-1)^2洛必达法则