lg8+lg125-lg2-lg5/log以5为底4的对数*log以2为底5的对数,+5*log以5为底2的对数+16ˆ3/4= 3lg2+3lg5-lg2-lg5/2*log以5为底2的对数*log以2为底5的对数+2+(2ˆ4)ˆ3/4 =3-1/2+2+8=11 2是怎样算出来的?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/09 00:48:24
lg8+lg125-lg2-lg5/log以5为底4的对数*log以2为底5的对数,+5*log以5为底2的对数+16ˆ3/4= 3lg2+3lg5-lg2-lg5/2*log以5为底2的对数*log以2为底5的对数+2+(2ˆ4)ˆ3/4 =3-1/2+2+8=11 2是怎样算出来的?
lg8+lg125-lg2-lg5/log以5为底4的对数*log以2为底5的对数,+5*log以5为底2的对数+16ˆ3/4
= 3lg2+3lg5-lg2-lg5/2*log以5为底2的对数*log以2为底5的对数+2+(2ˆ4)ˆ3/4 =3-1/2+2+8=11 2是怎样算出来的?
lg8+lg125-lg2-lg5/log以5为底4的对数*log以2为底5的对数,+5*log以5为底2的对数+16ˆ3/4= 3lg2+3lg5-lg2-lg5/2*log以5为底2的对数*log以2为底5的对数+2+(2ˆ4)ˆ3/4 =3-1/2+2+8=11 2是怎样算出来的?
5^log(5)2=2
log(5)2*log(2)5=1
(lg8+lg125-lg2-lg5)/[log(5)4*log(2)5]+5^log(5)2+16ˆ(3/4)
=﹙3lg2+3lg5-lg2-lg5﹚/[2log(5)2*log(2)5]+5^log(5)2+(2ˆ4)ˆ﹙3/4 ﹚ =﹙3-1﹚/2+2+8=11
计算lg8+lg125-lg2-lg5
求(lg2+lg5-lg125-lg8)/(lg10的立方根×lg0,001)
lg125+lg8+lg5lg20+(lg2)^2=
lg5^2+2/3lg8+lg5*lg20+lg2^2
(lg5)平方+2/3lg8+lg5乘lg20+(lg2)平方
化简[(1-lg5)^2+lg2乘lg5]/lg8
(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
比较lg5/lg2与lg8/lg5的大小
(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
3lg2+2lg5+lg5乘以lg8怎样算
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
(lg2)+(lg5)+lg5×lg8 怎么化简求值,
lg5乘以lg8是多少(lg2)^3+(lg5)^3+lg5乘以lg8 怎么算出来
lg5 (lg8+lg1000)+(lg2 )(lg2 )+lg0.06+lg1/6
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
(lg8+lg1000)lg5+3(lg2)^2+lg^-1+lg0.006