3lg2+2lg5+lg5乘以lg8怎样算
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3lg2+2lg5+lg5乘以lg8怎样算
3lg2+2lg5+lg5乘以lg8怎样算
3lg2+2lg5+lg5乘以lg8怎样算
3lg2+2lg5+lg5*lg8=3lg2+2lg5+3lg2*lg5=lg2+2+3lg2*lg5=1g2+lg2^2+lg5^2+7lg2*lg5=(2lg2+lg5)(2lg5+lg2)+2lg2*lg5+lg2=(1+lg2)(1+lg5)+2lg2*lg5+lg2=(1+lg5)(2+lg2)+lg2*lg5=算不动了,我先下去算一下
3lg2+2lg5+lg5乘以lg8怎样算
lg5乘以lg8是多少(lg2)^3+(lg5)^3+lg5乘以lg8 怎么算出来
化简2lg5+2/3lg8+lg5乘以lg20+lg2的平方急,
lg5的平方+2/3lg8+lg5乘以lg20+(lg2)的平方=?紧急!
lg5^2+2/3lg8+lg5*lg20+lg2^2
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
(lg5)平方+2/3lg8+lg5乘lg20+(lg2)平方
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
lg5^2+2/3lg8+lg5*lg20+(lg2)^2 lg5*lg20怎么办啊
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
对数lg2*lg5=?2lg(5)+2/3 lg8+lg5*lg20+lg2 =lg5^2+lg8^(2/3)+lg5*(lg4+lg5)+lg2 =lg100+lg5+2lg2*lg5+lg2 =2+(lg5+lg2) =2+1 =3 第二个等号lg5*(lg4+lg5)为什么=lg5+2lg2*lg5
lg25+2/3lg8+lg5·lg20+lg^22我见到个过程是lg25+2/3lg8+lg5乘以lg20+lg^22=2lg5+2lg2+lg5*(2lg2+lg5)+lg2*lg2=2(lg5+lg2)+(lg5)^2+2lg2*lg5+(lg2)^2=2lg10+(lg5+lg2)^2=2+1^2=3 我想问一下,第3步怎么到第4步的?错了,是第2步怎么到第3
lg5(2)+2/3lg8+lg5*lg2+(lg2)^2
计算:(lg2)2+3lg5+lg5(1+lg2)+lg8+log2(5)log5(4)
lg25+2/3lg8+lg5*lg20+(lg2)^2
(lg2)^2+lg25+2/3lg8+lg5*lg20=?