(lg2)+(lg5)+lg5×lg8 怎么化简求值,
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 22:10:16
(lg2)+(lg5)+lg5×lg8 怎么化简求值,
(lg2)+(lg5)+lg5×lg8 怎么化简求值,
(lg2)+(lg5)+lg5×lg8 怎么化简求值,
计算lg8+lg125-lg2-lg5
lg5^2+2/3lg8+lg5*lg20+lg2^2
(lg5)平方+2/3lg8+lg5乘lg20+(lg2)平方
化简[(1-lg5)^2+lg2乘lg5]/lg8
(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
比较lg5/lg2与lg8/lg5的大小
(lg2)^3+(lg5)^3+lg5*lg8怎么算谢谢!
lg5^2+lg8^2/3+lg5*lg20+(lg2)^2=?
3lg2+2lg5+lg5乘以lg8怎样算
lg5²+2/3lg8+lg5*lg20+(lg2)²
lg5²+2/3lg8+lg5×lg20+(lg2)²
(lg2)+(lg5)+lg5×lg8 怎么化简求值,
lg5乘以lg8是多少(lg2)^3+(lg5)^3+lg5乘以lg8 怎么算出来
lg2+lg5=?1-lg2=?1-lg5=?2lg5+2/3lg8+lg5*lg20+(lg2)2=?
lg5+lg5*lg2+lg2*lg2
lg5 (lg8+lg1000)+(lg2 )(lg2 )+lg0.06+lg1/6
lg5^2+2/3lg8+lg5*lg20+(lg2)^2 lg5*lg20怎么办啊
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,