若X=2004则(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)=?
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若X=2004则(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)=?
若X=2004则(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)=?
若X=2004则(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)=?
(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)
=(5x^3-x^3-4x^3)+(3x^2-2x^2-x^2)+(3x-2x-x-x)+(19+4-1)
=-x+22
∵X=2004
∴(5x^3-2x^2+3x-1)+(-x^3-2x+3x^2+4)-(4x^3+x^2+x+x-19)=-2004+22=-1982
x=2003呢?
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*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
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