log5[log3(log2^x)]=1,x=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 06:34:27
log5[log3(log2^x)]=1,x=
log5[log3(log2^x)]=1,x=
log5[log3(log2^x)]=1,x=
log5[log3(log2^x)]=x log(5+3+2)=x =1,可得x=1
log5[log3(log2^x)]=1,x=
log2[log3[log5 125]]=?log2[log3[log5 125]]=?
log5[log2(log9/log3)]=?
若log2(x)=log3(y)=log5(z)
如果log5[log3(log2 x)]=0,那么x^(1/3)等于
log2(log5 x)=-1
log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=?
计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15
已知log2[log4(log3x)]=log3[log5(log2y)]=0,求4更号x-y^1/5
已知log2[log4(log3x)]=log3[log5(log2y)]=0,求4更号x-y^1/5写过程
(log2)和(log3)变成(log5)
1/log5^7+1/log3^7+1/log2^7 ,求值
log2(a)=log3(b)=log5(c)
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
log3 25×log2 27×log5 2^-3=_____
log5[log2(log3 9)]=
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X