log5[log2(log3 9)]=
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log5[log2(log3 9)]=
log5[log2(log3 9)]=
log5[log2(log3 9)]=
log3 9=2 log2 2=1 log5 1=0
所以最后结果是零
原式=log5[log2(2)]
=log5(1)
=0
log5[log2(log3 9)]=
log2[log3[log5 125]]=?log2[log3[log5 125]]=?
log5[log2(log9/log3)]=?
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
log2(25)乘log3(4)乘log5(9)=?
(log3^4+log5^2)(log2^9+log2^根号3)
(log2)和(log3)变成(log5)
高中对数log2(9)*log3(根号5)*log5(2)
利用换底公式求值.log2(25)×log3(4)×log5(9)
log5怎么表示(已知log2=a,log3=b)
高中数学题log2^25 * log3^4 * log5^9
log2(a)=log3(b)=log5(c)
若log2(x)=log3(y)=log5(z)
log5[log3(log2^x)]=1,x=
log3 25×log2 27×log5 2^-3=_____
log2(3)*log3(5)*log5(8)(具体步骤)
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X