数列{an}的前n项之和为Sn,Sn=1-2/3an,则an=

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数列{an}的前n项之和为Sn,Sn=1-2/3an,则an=
数列{an}的前n项之和为Sn,Sn=1-2/3an,则an=

数列{an}的前n项之和为Sn,Sn=1-2/3an,则an=
sn+1-sn=an+1=-2/3(an+1-an),an+1=2an s1=a1,1-2/3a1=a1,a1=3/5.
a2=2a1=2 (3/5),an=2^(n-1)(3/5)

  • SN=1-2/3AN,

S(N-1)=1-2/3A(N-1);

AN=2/3*(A(N-1)-AN)

5/3AN=2/3A(N-1)

AN/A(N-1)=2/5;

A1=1-2/3A1;A1=3/5;

AN=3/5*(2/5)^(n-1) 

sn+1-sn=an+1=-2/3(an+1-an),
an+1=2an
s1=a1,
1-2/3a1=a1,
a1=3/5.
a2=2a1=2 (3/5),
an=2^(n-1)(3/5)
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