数列{an}满足=3an-1+3^n-1,(n≥2),a4=365,an的前n项之和为Sn,求Sn
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 22:45:29
数列{an}满足=3an-1+3^n-1,(n≥2),a4=365,an的前n项之和为Sn,求Sn
数列{an}满足=3an-1+3^n-1,(n≥2),a4=365,an的前n项之和为Sn,求Sn
数列{an}满足=3an-1+3^n-1,(n≥2),a4=365,an的前n项之和为Sn,求Sn
a1=5
an=-3^n/2+2 (n≥2)
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an满足a1=1/3,Sn=n(2n-1)an,求an
数列[An]满足a1=2,a(n+1)=3an-2 求an
已知数列{an}满足a1=1,an=(an-1)/3an-1+1,(n>=2,n属于N*),求数列{an}的通项公式
已知数列{an}满足a1=4/3,且an+1=4(n+1)an/3an+n
数列{an}满足a1=1,an=3n+2an-1(n≥2)求an
数列an满足,a1=1/4,a2=3/4,an+1=2an-an-1(n≥2,n属于N*),数列bn满足b1
已知数列an满足a1=3,An+1=2An+2^n (1)求证数列[An/2^n]是等差数列 (2)求an通项公式
已知数列an满足a1=1,a(n+1)=an/(3an+1) 求数列通项公式
若数列【an】满足a1等于1,An+1=2an+3n,则数列的项A5
数列{an)满足an=4a(n-1)+3,a1=0,求数列{an}的通项公式
已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn
已知数列{an}满足a1=1 ,an+1=3an+2的n+1次幂,求an
已知数列an满足a1=1,a(n+1)=an/(3an+2),则an=?
已知数列(an)满足a1=1.an+1=3an+2n-1,求an
数列{an]满足a1=1且an+1=an+3n次方,求an通项公式
已知数列{an}满足a1=4,3an=5an(n下-1) +1,求an
已知数列(an)满足an+1=2an+3×2∧n,a1=2求an