(2x+y)∧2-(x+2y)∧2
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(2x+y)∧2-(x+2y)∧2
(2x+y)∧2-(x+2y)∧2
(2x+y)∧2-(x+2y)∧2
原式=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
纯手打~求采纳>
=(2x加y-x-2y)(2x加y加x加2y)
=(x-y)(3x 3y)
=3(x^2-y^2)
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[(x-y)^2-(x+2y)(x-2y)]/y
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x^2(x-y)+(y-x)
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(2x+y)∧2-(x+2y)∧2
化简:[(x+y)(x-y)(x+y)^2-2y(x-2y)](-2y) 谢谢!
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