lingo 错误1017min=0.4*(sqrt(2*150^2+(65*sqrt(2)+10)^2-2*(65*sqrt(2)+10)*p)+p*(1+exp(10-0.1*p^2))*atan(p/sqrt(2*150^2+(65*sqrt(2)+10^2)-2*(65*sqrt(2)+10)*p)));p^2-(65*sqrt(2)-p)^2
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lingo 错误1017min=0.4*(sqrt(2*150^2+(65*sqrt(2)+10)^2-2*(65*sqrt(2)+10)*p)+p*(1+exp(10-0.1*p^2))*atan(p/sqrt(2*150^2+(65*sqrt(2)+10^2)-2*(65*sqrt(2)+10)*p)));p^2-(65*sqrt(2)-p)^2
lingo 错误1017
min=0.4*(sqrt(2*150^2+(65*sqrt(2)+10)^2-2*(65*sqrt(2)+10)*p)+p*(1+exp(10-0.1*p^2))*atan(p/sqrt(2*150^2+(65*sqrt(2)+10^2)-2*(65*sqrt(2)+10)*p)));
p^2-(65*sqrt(2)-p)^2
lingo 错误1017min=0.4*(sqrt(2*150^2+(65*sqrt(2)+10)^2-2*(65*sqrt(2)+10)*p)+p*(1+exp(10-0.1*p^2))*atan(p/sqrt(2*150^2+(65*sqrt(2)+10^2)-2*(65*sqrt(2)+10)*p)));p^2-(65*sqrt(2)-p)^2
min=0.4*(@sqrt(2*150^2+(65*@sqrt(2)+10)^2-2*(65*@sqrt(2)+10)*p))+p*(1+@exp(10-0.1*p^2))*@atan(p/@sqrt(2*150^2+(65*@sqrt(2)+10^2)-2*(65*@sqrt(2)+10)*p));
p^2-(65*@sqrt(2)-p)^2
LINGO 错误1017min=7.2*(((x1^2+(y1-5)^2)^(1/2))+((x1-15)^2+(y1-y2)^2)^(1/2)+(25+(8-y2)^2)^(1/2)+x1)+21*(25+(8-y2)^2)^(1/2)STx1>0x10y1
lingo 错误1017min=0.4*(sqrt(2*150^2+(65*sqrt(2)+10)^2-2*(65*sqrt(2)+10)*p)+p*(1+exp(10-0.1*p^2))*atan(p/sqrt(2*150^2+(65*sqrt(2)+10^2)-2*(65*sqrt(2)+10)*p)));p^2-(65*sqrt(2)-p)^2
lingo程序错误1017model:sets:question(/1..i/):x,y;endsetsinit:x(1)=0;y(1)=0;endinit[obj] max=@sum(link(i,j):c(i))@for(question:(min(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2))>=z););@for(question:(max(@sqrt((x(i)-x(i1))^2+(y(i)-y(j))^2))
lingo 错误的1017我在model后面打过:model:sets:para/1..3/:y;warehouses/wh1..wh3/:capacity;vendors/v1..v4/:demand;links(warehouses,vendors):cost,volume;endsets目标函数;min=@sum(links:cost*volume)+91y(1)+70y(2)+24y(3);@for(para:@bin(y));
lingo 错误1017 min=3203.5x1+4842.5x2+2980x3+4023x4+3650.5x5+4395.5x6+3312.5x7+4000x8+2625x9+3000x10+3500x11+3687.5x12+3125x13+480x14+278.4x15+480x16+432x17+480x18+19.2x19+19.2x20+38.4x21+57.6x22+57.6x23+240x24;1.27664a1+1.938396a2+1.27664a3+1.63779
lingo中这样求解对么 为什么运行错误?Min= (x^2-(2-y)^2)^1/2+((4-x)^2+(4-y)^2)^1/2+y X<=4 Y<=4
LINGO错误提示index variables may not share names with other variablesdemand/1..8/:b;links(supply,demand):cost,x;endsets目标函数;min=@sum(links:cost*x);约束;@for(demand(J):@sum(supply(I):x(I,J))
lingo矩阵输入错误29
lingo矩阵输入错误29
lingo中输入min=x;1312.5x-y7.79为什么老是显示unexpected jacobian o
lingo@min与@smin的区别
lingo 错误1017怎么办啊model:min=x1+x2+x3;x1*r11+x2*r12+x3*r13>=60;x1*r21+x2*r22+x3*r23>=11;x1*r31+x2*r32+x3*r33>=34;x1*r41+x2*r42+x3*r43>=20;5*r11+6*r21+9*r31+11*r41>=21;5*r12+6*r22+9*r32+11*r42>=21;5*r13+6*r23+9*r33+11*r43>=21;5*r11+6*r21+9*r3
lingo错误1017怎么办,在线等,急min=(a1+a2+a3+a4+a5+a6+a7+a8+a9+a10+b1+b2+b3+b4+b5+b6+b7+b8+b9+b10+c1+c2+c3+c4+c5+c6+c7+c8+c9+c10)*2000+(d1+d2+d3+d4+d5+d6+d7+d8+d9+d10+e1+e2+e3+e4+e5+e6+e7+e8+e9+e10+h1+h2+h3+h4+h5+h6+h7+h8+h9+h10+i1+i2+i3+i4+i5
lingo矩阵怎样用lingo软件或者MATLAB写出规划问题解min=sum|x(i)-c(i)|*d(i)条件a(i)
LINGO min 45;(x1+x2) ST x1+x2>=1 x1min 45;(x1+x2)STx1+x2>=1x1
lingo中min=sqrt(x^2+(y-a)^2)+sqrt((x-b)^2+(y-c)^2)+y;为啥不对
lingo程序显示结果错误sets: warehouses/wh1..wh3/: capacity; vendors/v1..v4/: demand; links(warehouses,vendors): cost, volume;endsetsdata: capacity=50 65 70; demand=35 37 22 32; cost=6 2 6 7 4 9 5 3 5 2 1 9 enddata min=@s
lingo求解min=x1^2+x1*x2+x2^2-60*x1-3*x2;结果错误Objective value:-900.0,此时X1=30.0,X2=0.0 但当x1,x2分别为39和-18时才取最小-1143怎么回事儿?并且改变x2系数时结果都一样:即将上式中-3改为3、5、6、7……结