5c/6a^2b+7a/8b^2c-b/12a^2c

初二分式的加减法2a-b-c/（a-b)(a-c)+ 2b-c-a/(b-c)(b-a)+ 2c-b-a/(c-b)(c-a)3a-6b/a+b- 5a-6b/a-b- 4a-5b/a+b+ 7a-8b/b-a注：有空格的地方是下一个分式 化简：7(a-b-c)-5(a+b-c)+3(a-b-c)+(a+b-2) 2a(a+b-c)-3b(a+b-c)+5c(c-a-b) 5a+{3b+[6c-2a-2(a-c)]}-[9a-(7b+c)] 5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c）] 5a-｛-3b+[6c-2a-(a-c)}-[9a-(7b+c)] 5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)] 计算：5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)] 5c/6a^2b+7a/8b^2c-b/12a^2c 5c/6a^2b+7a/8b^2c-b/12a^2c通分计算 [b/(a-b+c)]+[(2a+c)/(b-a-c)]-[(b-c)/(b-a-c)] b/a-b+c+2a+c/b-a-c-b-c/b-c-a a-c+b=5 a+b+c=7 a-b-c=2 求a b c a+6b等于c,2a-2b等于5c,求a:b;c (a-b+c/a+b-c)-(a-2b+3c/b-c+a)+(b-2c/c-a-b) 已知5a=8b,7c=2b,求a:b:c 已知a+b/2=b-2c/3=3c-a/4,则5a+6b-7c/8a+9b=_________ 已知(a+b)/2=(b-2c)/3=(3c-a)/4,求(5a+6b-7c)/(8a+9b)的值.