5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
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5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
=5a-{-3b+[6c-2a-a+c]}-[9a-7b-c]
=5a-{-3b+6c-2a-a+c}-9a+7b+c
=10b-3a-6c
注:别忘了写解,希望以后自己多动动脑筋
5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
=5a-{-3b+[6c-2a-a+c]}-[9a-7b-c]
=5a-{-3b+6c-2a-a+c}-9a+7b+c
=5a+3b-6c+2a-a-c-9a+7b+c
=-3a+10b-6c
先算小括号,再算中括号,然后大括号!还有就是括号外面是减号的话,那么去掉括号原先括号里面的符号要变(比如说原来是加号,去括号就变成减号)!
3a+10b-6c
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5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
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5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
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计算题5a-{-3b+[6c-2a-(a-c)]}-[9a-(7b+c)]
a+6b等于c,2a-2b等于5c,求a:b;c
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