(2x+3y)除以(5x-3y)=3/5求x比y
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(2x+3y)除以(5x-3y)=3/5求x比y
(2x+3y)除以(5x-3y)=3/5求x比y
(2x+3y)除以(5x-3y)=3/5求x比y
分子分母同时除以Y 令x比y =Z 即使求Z=?(2Z+3)/(5z-3)=3/5 15Z-9=10Z+15 Z=24/5
(2x+3y)除以(5x-3y)=3/5 3*(5x-3y)=5*(2x+3y) 15X-9y=10X+15y 15X-10X=15y+9y 5X=24y X:y=24:5
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
(2x+3y)除以(5x-3y)=3/5求x比y
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