化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/14 22:29:31
化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)=-sinacosa/(-cosacosa)=tana
sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
=sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
=sin(3π+α)cos(2π-α)/sin(3π/2+α)cos (5π-α)
= -sinαcosα/-cos α*(-cos α)
=-tanα
化简cos(540°-α)sin(α-360°)/sin(-α+180°)cos(180°+α)
化简sin(540°+α)cos(360°-α)/sin(450°+α)cos (900°-α)
化简,cos²(-α)-tan(360°+α)/sin(-α)
化简cos^2(-α)-[tan(360°+α)/sin(-α)]
.[1/cos(-α)+cos(180°+ α )]/[1/sin(540°-α)+sin(360°-α)]=tan^3α
cos(540-α)sin(α-360)/sin(-α+180)cos(180+α)
Cos(180°+α)*sin(α+360°)/sin(-α-180°)*cos(-180°-α)
sinα+cosα 化简
化简①sin(π+α)×cos(3π/α)+sin(π/2+α)×cos(π+α)②sin(540°-x)×cos(x-360°)/tan(900°-x)×tan(450°-x)×tan(810°-x)×sin(-x)
已知α=1050°,化简sin(540°-α)/tan(α-180°)×sin(-α-360°)/cos(720°-α)
求证:(1/sinα-sin(180°+α))/(1/cos(540°-α)+cos(360°-α))=1/(tanα)^3
化简sin(540°-a)tan (a-180°)cos(a-270°)/cos(a-360°)tan(720°+a)sin(-a-360°)过程、速度速度!
化简:1+sin(α—360°)cos(α—270°)—2(cosα)^2
sin(540°+α)cos(360°-α)/sin(450°+α)tan(900°-α)急!
化简cos(45°-α)-sin(45°+α),得
化简cos(α+30°)cos(α-30°)-sin(α+30°)sin(α+150°),化简cos(α+30°)cos(α-30°)-sin(α+30°)sin(α+150°),
化简:tanα(cosα-sinα)+sinα(sinα+tanα)/1+cosα.
化简:cos(90°-a)/sin(270°+a)·sin(180°-a)·cos(360°-a)=