化简cos(45°-α)-sin(45°+α),得
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化简cos(45°-α)-sin(45°+α),得
化简cos(45°-α)-sin(45°+α),得
化简cos(45°-α)-sin(45°+α),得
cos(45°-α)-sin(45°+α),
=cos45°cosα-sin45°sinα-(sin45°cosα+cos45°sinα)
=cos45°cosα-sin45°sinα-sin45°cosα-cos45°sinα
=cos45°cosα-cos45°cosα-sin45°sinα-cos45°sinα
=-√2/2sinα-√2/2sinα
=-√2 sinα
化简cos(45°-α)-sin(45°+α),得
化简 sin(θ+75°)+cos(θ+45°)+cos(θ+15°)化简题sin(θ+75°)+cos(θ+45°)+cos(θ+15°)
-cos(α-45°)=sin(α+45°)对吗?
化简cos(45°-a)cos(a+15°)-sin(45°-a)sin(a+15°)的结果为
化简:(5)cos(α-45°)cos(15°+α)+sin(α-45°)sin(15°+α)
化简[tan(45°-α)]/[1-tan²(45°-α)]*[(sinα*cosα)/(cos²α-sin²α)]
sin(a+45°)sin(a+15°)+cos(a+45°)cos(a+15°)
己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
cos²45°/sin²45°-tan45°
化简,cos²(-α)-tan(360°+α)/sin(-α)
化简cos^2(-α)-[tan(360°+α)/sin(-α)]
化解cos(45°-a)-sin(45°+a)
Sin^2 45°+cos^2 45°=?
化简cos(α+30°)cos(α-30°)-sin(α+30°)sin(α+150°),化简cos(α+30°)cos(α-30°)-sin(α+30°)sin(α+150°),
cos 60°+sin 45°-tan 30°=?
cos tan sin 30° 45° 60°是多少
sin ²45° +cos²30°
2tan(45°-α)]/[1-tan²(45°-α)]*[(sinα*cosα)/(cos²α-sin²α)]