lim(x→0) xsinx
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 03:26:20
lim(x→0) xsinx
lim(x→0) xsinx
lim(x→0) xsinx
用到一条性质,无穷小与一个有界函数的乘积仍为无穷小,因此lim(x→0) xsinx =0
0
lim(x→0) xsinx
lim(x→0)(1-cos4x)/xsinx
lim(x→0)(1-cos2x)/xsinx
lim(x→0) sinx-x(x+1)/xsinx
lim(e^2-x)/xsinx x→0 怎么求?
求极限lim x→0 (1/xsinx+xsin1/x)
求下列极限lim(x→0)(1-cosx)/xsinx
lim(x→0)(1-cosx)/(xsinx)=?
2.5计算极限lim(x→0) (1-cos2x)/xsinx
lim(x→ 0)(tanx-sinx)/xsinx^2
lim xsinx/(arctan3x^2)x→0
求极限Lim(x→0)1/xsinx-1/xtanx
lim(x→-∞)e^xsinx
lim(x趋向0) 1-cos2x/xsinx
lim(x->0)(2xsinx)/(secx-1)
求lim┬(x→0)〖x^2+x-tanx/xsinx
lim (tanx-sinx)/x (x→0)的极限; lim (1-cos4x)/xsinx (x→0)的极限
求极限x→0时,lim[√(1+xsinx)–cosx]/x²