1-2+3-4+5.-1992+1993如题:
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1-2+3-4+5.-1992+1993如题:
1-2+3-4+5.-1992+1993
如题:
1-2+3-4+5.-1992+1993如题:
原封不动的找到了答案,小学4年级的吧,呵呵
1-2+3-4+5-6+……+1991-1992+1993
=1+(3-2)+(5-4)+.+(1993-1992)
=1+[(1993-1)/2]*1`
=1+996
=997
1+1993+(-2-1992)=0
类推,都抵消了,最后剩下最中间的数
等于(1+1993)/2=997
997
正确答案是:997
1-2+3-4+5....-1992+1993
=(1-2)+(3-4)+(5-6)+...+(1991-1992)+1993
=-996+1993
=997
1-2+3-4+5....-1992+1993
=1+(-2+3)+(-4+5)....+(-1992+1993)
=1+1+1....+1(加了997次)
=997
1-2+3-4+5-6+……+1991-1992+1993
=1+(3-2)+(5-4)+.....+(1993-1992)
=1+[(1993-1)/2]*1`
=1+996
=997
1-2+3-4+5-6....-1992+1993
=1+(3-2)+(5-4)+(7-6)+(9-8)+…+(1993-1992)
=1+1+1+1+1+…+1(总共有1992/2+1=997个1)
=997
最后答案为997。
回答的好的话望采纳。
哈哈,太简单了吧?简直是在低估我的IQ,是997
1-2+3-4+5-6+……+1991-1992+1993
=(1-2)+(3-4)+(5-6)+……+(1991-1992)+1993
=-1*1992/2+1993
=-996+1993
=997
答案是:997
1-2+3-4+5....-1992+1993
=(1-2)+(3-4)+(5-6)+...+(1991-1992)+1993
=-996+1993
=997
997
997