若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.

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若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.

若x、y满足x2+2y2-2xy-2y+1=0,求xy的值.
x^2+2y^2-2xy-2y+1=0
x^2-2xy+y^2+y^2-2y+1=0
(x-y)^2+(y-1)^2=0
x=y=1
xy=1
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x2+y2+y2-2xy-2y+1=0
x2+y2-2xy+y2-2y+1=0
（x-y）2+（y-1）2=0
因为是都是平方，都不小于0，所以都为0
y-1=0 .y=1
x-y=0 .x=1
xy=1
手机码出来累死了。。

x=1 y=1 xy=1

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