若X1满足2X+2^X=5,X2满足2X+2log2（X-1)=5,（2log2(x-1)中（x-1)前的2为底数） 求X1+X2

若x1满足2x+2^x=5,x2满足2x+2log2(x-1)=5 100分若x1满足2x+2的x次方=5,x2满足2x+2log2(x-1)=5,则x1+x2=? 若x1满足2x+2x=5,x2满足2x+2log2(x-1)=5,则x1+x2等于? 若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2 若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2 若x1,x2都满足条件|2x-1|+|2x+3|=4,且x1 若X1.X2都满足条件|2X-1|+|2X+3|=4,且X1 若x1满足2x+2^x=5.x2满足2x+2log2(x-1)=5.求x1+x2=? x1满足2x+2^x=5,x2满足2x+2log2(x-1)=5,x1+x2=? 若x1满足2x+ 2^x=6,x2满足x+ log2(x-1)=3,则x1+ x2=? 若X1满足2X+2^X=5,X2满足2X+2log2（X-1)=5,（2log2(x-1)中（x-1)前的2为底数） 求X1+X2 若x1满足2x+2x=5,x2满足2x+2log2(x-1)=5,则x1+x2等于?答案我知道,关键是2x1为什么等于7-2t. 若x1满足2x+2^x=5,x2满足2x+log2(x-1)=5,则x1+x2=?这样可以化简到 2^(x1-1)=1.5-(x1-1)log2(x2-1)=1.5-(x2-1)因为y=2^x与y=log2(x)互为反函数 为什么有x1-1+x2-1=1. 已知方程x^2+8x+k=0两根x1,x2,满足x1--2x2=1,求k是满足X1-2倍的X2 若x1满足2x+2^x=5,x2满足2x+2log2(x-1)=5,则x1+x2=?2log2(x-1) 中间的2是底,我搞半天都不懂 若x1、x2、都满足｜2x-1｜+｜2x+3｜=4,且x1＜x2,则x1-x2的取值范围是? 若x1、x2,都满足条件│2x-1│+│2x+3│=4,且x1 若X1满足2X+2∧X=5,X2满足2X+2㏒2（X-1）=5,则X1+X2等于（ ）A5/2 B3 C7/2 D4