sin(6/π-α)=1/3,则cos(2π/3+2α)的值为
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sin(6/π-α)=1/3,则cos(2π/3+2α)的值为
sin(6/π-α)=1/3,则cos(2π/3+2α)的值为
sin(6/π-α)=1/3,则cos(2π/3+2α)的值为
cos(2π/3+2α)
= - cos(π-(2π/3+2α))
=- cos(π/3-2α)
=- cos(2α-π/3) (公式cos2α=1-2(sinα)^2)
=- (1-2(sin(α-π/6))^2)
∵sin(π/6-α)=1/3
∴sin(α-π/6))^2=1/9
故cos(2π/3+2α)
= -(1-2*1/9)
=-7/9
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