{7x+3y-5z=8 y:x:z=5:3:8
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{7x+3y-5z=8 y:x:z=5:3:8
{7x+3y-5z=8 y:x:z=5:3:8
{7x+3y-5z=8 y:x:z=5:3:8
x等于10y为6z为16
x+y-z=3 y+z-x=5 z+x-y=7 求x,y,z
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2
已知:x+y+z=0,5x-3y-z=0,求:5x-y+z/2x+8y+7z 的值
已知关于x y z的方程组2x-3y+5z=7 x+2y-3z=8,则4x+y-z=
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
三元一次方程组2x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=262x+z=3 3x+y-z=8 x+3y+2z=3 5x+2y-3z=2 x+2y+z=6 7x-2y-4z=26
2x+3y-z=11 2x+y-5z=8 -2+7y+z=19
x/2=y/3=z/5 x+3y-z/x-3y+z
x+y+z=1 x+3y+7z=-1 x+5y+8=2题错了 x+y+z=1 x+3y+7z=-1 x+5y+8z=2
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z)
{7x+3y-5z=8 y:x:z=5:3:8
已知x+7y+8z=3,3x-y+2z=5,求x+y+2z的值x+7y+8z=3,3x-y+2z=5是一个方程组
{x+y+z=1 x-2y+3z=5 2x-3y-3z=-8
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?