已知数列{An},Sn=0.125(An+2)(An+2).求证:{An}是等差数列
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/14 07:24:26
已知数列{An},Sn=0.125(An+2)(An+2).求证:{An}是等差数列
已知数列{An},Sn=0.125(An+2)(An+2).求证:{An}是等差数列
已知数列{An},Sn=0.125(An+2)(An+2).求证:{An}是等差数列
由S(n-1)=Sn-An
将Sn带入,两端乘以8得:(A(n-1)+2)(A(n-1)+2)=(An-2)(An-2)
开方,有An-A(n-1)=4,所以:{An}是等差数列,公差为4,首项为2.通项公式:An=4n-2
An+2是什么啊是(An)+2,还是A(n+2)
已知数列{An},Sn=0.125(An+2)(An+2).求证:{An}是等差数列
已知数列an,Sn>1,6Sn=(an +1)(an +2) 求通项
已知数列{an}中,an>0,s=a1+a2+.+an,且an=6sn/(an+3),求sn
“已知数列{an}中,an>0,Sn是数列{An}中的前n项和,且An+1/An=2Sn”An>0,求An
已知数列 an>0 an+1/an=2Sn 求an
已知数列{an}中,an>o,且2Sn=an2+an,求an
已知数列an,an属于n*,sn=1/8*(an+2)^2,{an}是等差数列
已知数列{an}满足:a1=3,an=Sn-1+2n,求数列an及sn
一个数列问题已知数列an前n项为sn,满足an+sn=2n.求an
一道关于数列 已知数列{An}的前n项和为Sn,Sn=3+2An,求An
已知数列{an}的前n项和为Sn,an+Sn=2,(n
已知数列 {an}中,a1=56,an+1=an-12 求Sn的最大值
已知数列{an},满足a1=1/2,Sn=n²×an,求an
已知数列{an}满足a1=1/2,sn=n^2an,求通项an
已知数列an满足a1=1/2 sn=n平方×an 求an
已知数列An满足 A1=1/2 Sn=N²An 求An
已知数列an满足a1=1 Sn=2an+n 求an
已知数列{an}满足Sn+an=2n+1.求an