两个非零自然数X,Y的最大公因数是14,最小公倍数是280,它们的和是多少
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两个非零自然数X,Y的最大公因数是14,最小公倍数是280,它们的和是多少
两个非零自然数X,Y的最大公因数是14,最小公倍数是280,它们的和是多少
两个非零自然数X,Y的最大公因数是14,最小公倍数是280,它们的和是多少
X=14A,Y=14B,A和B没有公约数了,14*A*B=280,A*B=20,A+B=9,X+Y=14*9=126
一个是56一个是70,和为126
14+14 = 28
14 + 28 = 42
14 + 56 = 70
14 + 70 = 84
14 + 140 = 154
14 + 280 = 294
28 + 14 = 42
28 + 28 = 56
28 + 56 = 84
28 + 70 = 98
28 + 140 = 168
28 + 280...
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14+14 = 28
14 + 28 = 42
14 + 56 = 70
14 + 70 = 84
14 + 140 = 154
14 + 280 = 294
28 + 14 = 42
28 + 28 = 56
28 + 56 = 84
28 + 70 = 98
28 + 140 = 168
28 + 280 = 308
56 + 14 = 70
56 + 28 = 84
56 + 56 = 112
56 + 70 = 126
56 + 140 = 196
56 + 280 = 336
70 + 14 = 84
70 + 28 = 98
70 + 56 = 126
70 + 70 = 140
70 + 140 = 210
70 + 280 = 350
140 + 14 = 154
140 + 28 = 168
140 + 56 = 196
140 + 70 = 210
140 + 140 = 280
140 + 280 = 420
280 + 14 = 294
280 + 28 = 308
280 + 56 = 336
280 + 70 = 350
280 + 140 = 420
280 + 280 = 560
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14(x+y)=280
x+y=20
126