设y=tanx^3-2^-x,求dy
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设y=tanx^3-2^-x,求dy
设y=tanx^3-2^-x,求dy
设y=tanx^3-2^-x,求dy
dy=d(tan(x^3)-2^-x)
=sec²(x³)d(x³)+2^(-x)ln2dx
=[3x²sec²(x³)+2^(-x)ln2]dx
y=(tanx^3) -2^(-x)
dy = [3x^2.(secx^3)^2 +(ln2)2^(-x)]dx
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