SINX+根号3COSX=2SIN(X+π/3)是怎样推导算出来的
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SINX+根号3COSX=2SIN(X+π/3)是怎样推导算出来的
SINX+根号3COSX=2SIN(X+π/3)是怎样推导算出来的
SINX+根号3COSX=2SIN(X+π/3)是怎样推导算出来的
sinx+√3cosx=2[(1/2)sinx+(√3/2)cosx]
=2[sinxcos(π/3)+sin(π/3)cosx]
=2sin(x+π/3)
利用公式sinαcosβ+cosαsinβ=sin(α+β)
sinx+√3cosx
=2(1/2sinx+√3/2cosx)
=2(cosπ/3sinx+sinπ/3cosx)
=2sin(x+π/3)
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证明:Sinx+(根号3)*Cosx=2Sin(x+π/3)
SINX+根号3COSX=2SIN(X+π/3)是怎样推导算出来的
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