1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
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1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
=1/2(1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7+1/6-1/8+1/7-1/9+1/8-1/10+1/9-1/11+1/10-1/12+1/11-1/13)=1/2(1/2+1/3-1/12-1/13)=35/104
0.3365384615384615
1/3+1/8+1/15+1/24+1/35+...+1/80+1/99 怎么解
1/3+1/8+1/15+1/24+1/35+1/48
1/3,-1/8,1/15,-1/24,1/35,-1/48怎样找规律
1/3+1/8+1/15+1/24+1/35+.1/9999=
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99怎么求
(1/8+1/15+1/24+1/35+1/48)*2
观察1列数0,3,8,15,24,35,.
1/8+1/24+1/48+1/80+1/120的简便算法1/3+1/15+1/35+1/63+1/99+1/143
用简便方法计算:1/8+1/15+1/24+1/35+···+1/80+1/99
3分之1+8分之1+15分之1+24分之1+35分之1+48分之1等于多少
1/3+1/8+1/15+1/24+.1/9800
1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
(1+1/3)*(1+1/8)*(1+1/15)*(1+1/24)*.*(1+1/9800)
初一找规律-3/1,8/1,-15/1,24/1,-35/1……第n个数( )
1,3,8,15,24,( ).
8/1+15/1+24/1+```````+143/1
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80=?要简便算法啊,
观察下面一列数,探求其规律:3分之1,负8分之1,15分之1,负24分之1,35分之1,负48分之1