作业帮(1/8+1/15+1/24+1/35+1/48)*2
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(1/8+1/15+1/24+1/35+1/48)*2
(1/8+1/15+1/24+1/35+1/48)*2
(1/8+1/15+1/24+1/35+1/48)*2
=2/8+2/15+2/24+2/35+2/48
=1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7+1/6-1/8
=1/2+1/3-1/7-1/8
=95/168
x+y=xy<=[(x+y)/2]²
令a=x+y
则a<=(a/2)²
a²-4a>=0
a(a-4)>=0
显然a=x+y>0
所以a-4>=0
a>=4
所以x+y最小值是4
1/3+1/8+1/15+1/24+1/35+...+1/80+1/99 怎么解
1/3+1/8+1/15+1/24+1/35+1/48
1/3,-1/8,1/15,-1/24,1/35,-1/48怎样找规律
1/3+1/8+1/15+1/24+1/35+.1/9999=
(1/8+1/15+1/24+1/35+1/48)*2
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99怎么求
观察1列数0,3,8,15,24,35,.
用简便方法计算：1／8+1／15+1／24+1／35+···+1／80+1／99
3分之1+8分之1+15分之1+24分之1+35分之1+48分之1等于多少
1/8+1/24+1/48+1/80+1/120的简便算法1/3+1/15+1/35+1/63+1/99+1/143
1/8+1/15+1/24+1/35+1/48+1/63+1/80+1/99+1/120+1/143=?
初一找规律-3/1,8/1,-15/1,24/1,-35/1……第n个数( )
1/3+1/8+1/15+1/24+.1/9800
1,3,8,15,24,( ).
(1+1/3)*(1+1/8)*(1+1/15)*(1+1/24)*.*(1+1/9800)
1/3+1/8+1/15+1/24+1/35+1/48+1/63+1/80=?要简便算法啊,
8/1+15/1+24/1+```````+143/1
1,8,15,24,35 第N个数是多少当N=1的时候 也不得1啊 数列