设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2001(3)=
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 10:58:17
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2001(3)=
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2001(3)=
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2001(3)=
-2
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2011(X)=
设 f(x)=sinx,f1(x)=f'(X),f2(X)=f1'(X).fn+1(X)=fn'(X) n属于N+ 求f2007(X)=?
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f(fk(x)),k=1,2,...则f2001(3)=
设f(x)=1+x/1-x,又记f1(x)=f(x),fk+1(x)=f[fk(x)],k=1,2...,则f2009(x)?A.-1/x B.x C.x-1/x+1 D.1+x/1-x
设f(x)=2x+1,f1(x)=f[f(x)],fn(x)=f[fn-1(x)],(n>1,n属于正实数) 求f1(x) f2(x) f3(x)归纳fn(x)表达式
设f(x)=f1(x)=(1+x)/(x-1) ,f n+1 (x)=f[fn(x)],则f2011(x)=
设f(x)=1/x(x
设f(x)=1-x,(x
设f(x)=|1-2x|,x∈[0,1],记f1(x)=f(x),f2(x)=f[f1(x)],f3(x)=f(f2(x)),.,fn+1(x)=f[fn(x)],试求方程fn(x)=1/2x在[0,1]上有几个根?
设F1(x)=sin3x,Fn+1(x)=F'n(x) (n为正整数),求Fn(x)?
已知f1(x)=|3^x-1|,f2(x)=|3^x-9|,且f(x)=f1(x),f1(x)f2(x).(3)当0
设f(x)二次可微,f(0)=0,f'(0)=1,又(x/1+x)f'(x)=f''(x),求f(x)
设f1(x)=2/(1+x),定义f(n+1)(x)=f1[fn(x)],an=[fn(0)-1]/[fn(0)+2],则a(2007)等于
设f(x)=(x平方-1)/(x-1) (x
设f(x)=(x平方-1)/(x-1) (x
设f(x)=x/2+1/x(x
已知函数f(x)=x/(1+|x|),设f1(x)=f(x),fn+1(x)=f[fn(x)],求f2(x),并求fn(x)通项公式
设f(x)满足f(1/x)=x/1-x设设f(x)满足f(1/x)=x/1-x ,则f(x+1)=?