2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
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2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²)]
=2x²-2xy-6x²+9xy-2x²+4x²-2xy+2y²
=(2-6-2+4)x²+(-2+9-2)xy+2y²
=-2x²+5xy+2y²
直接拆开啊
-2x²+9xy-2y²
5xy-2x²+2y²
整式乘法..1.3xy(x²y-xy²+xy)-xy²(2x²-xy+2x)2.(x-1)(x²-4x+3)-x(x²-5x+2)
2(x²-xy)-3(2x²-3xy)-2[x²-(2x²-xy+y²]=?
若x²+xy-2y²=0,则x²+3xy+y²/x²+y²
x²+xy-2y²=0则x²+3xy+y²/x²+y²
(xy-x²)÷[(x²-2xy+y²)÷xy]*[(x-y)÷x²]
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