carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 04:22:29
carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
carl has $9 more than david does.hilbert has 1/3 of the amout of carl.if they have a total amout of $61,how much does each of them have?
Let $x be the amount of Carl has,$(x-9) be the amount of David has and $(x/3) be the amount of Hibert.
x+(x-9)+(x/3)=61
7x-27=183
7x=210
x=30
Carl has $30,David has $21 and Hibert has $10
Carl 的钱比David多9 美元,Hilbert的钱是Carl的1/3,如果他们三人一共有61美元,他们三人各有多少美元?
设Carl 有x美元
∴David有(x-9)美元
Hilbert有(x/3)美元
∴x+(x-9)+(x/3)=61
7x=210
x=30
∴x-9=30-9=21
x/3=30...
全部展开
Carl 的钱比David多9 美元,Hilbert的钱是Carl的1/3,如果他们三人一共有61美元,他们三人各有多少美元?
设Carl 有x美元
∴David有(x-9)美元
Hilbert有(x/3)美元
∴x+(x-9)+(x/3)=61
7x=210
x=30
∴x-9=30-9=21
x/3=30÷3=10
答:Carl 有30美元,David有21美元,Hilbert有10美元
收起