已知0﹤α﹤π/2,sinα=4/5.(1)求tanα的值.(2)求cos2α﹢sin﹙α﹢π/2﹚的值
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已知0﹤α﹤π/2,sinα=4/5.(1)求tanα的值.(2)求cos2α﹢sin﹙α﹢π/2﹚的值
已知0﹤α﹤π/2,sinα=4/5.(1)求tanα的值.(2)求cos2α﹢sin﹙α﹢π/2﹚的值
已知0﹤α﹤π/2,sinα=4/5.(1)求tanα的值.(2)求cos2α﹢sin﹙α﹢π/2﹚的值
(1)
因为0﹤α﹤π/2,sinα=4/5
所以cosα=3/5
所以tanα=4/3
2)
cos2α﹢sin﹙α﹢π/2﹚
=2(cosα)^2-1+cosα
=2*(3/5)^2-1+3/5
=2*9/25-1+3/5
=8/25
cosa=√(1-sin²a)=±3/5
因为0﹤α﹤π/2
所以cos=3/5
cos2a+sin(a+π/2)
=cos2a+cosa
=cos²a-sin²a+cosa
=9/25-16/25+3/5
=8/25
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