若x-y=5,-xy=3,求(7x+4y+xy)-6(5/6y+x-xy)的值
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若x-y=5,-xy=3,求(7x+4y+xy)-6(5/6y+x-xy)的值
若x-y=5,-xy=3,求(7x+4y+xy)-6(5/6y+x-xy)的值
若x-y=5,-xy=3,求(7x+4y+xy)-6(5/6y+x-xy)的值
首先化简:原式=7x+4y+xy-5y-6x+6xy
=(x-y)+7xy
因为,x-y=5,-xy=3
所以原式=5-21=-16
楼上忘记加负号了~
(7x+4y+xy)-6(5/6y+x-xy)=x-y+7xy=5-21=16
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