若log3(x)=-1/log4(3),则x+x^2+.+x^n+.=
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若log3(x)=-1/log4(3),则x+x^2+.+x^n+.=
若log3(x)=-1/log4(3),则x+x^2+.+x^n+.=
若log3(x)=-1/log4(3),则x+x^2+.+x^n+.=
∵log3(x)=-1/log4(3),
∴log3 x=log3 4
∴x=4
∴x+x^2+.+x^n=[x^(n+1)-x]/(x-1)=[4^(n+1)-4]/3
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