用matlab求dx/(1+cos(x))的不定积分怎么求

用matlab求dx/(1+cos(x))的不定积分怎么求 ∫dxcos(x)dx用matlab该怎样表达,打比方有个式子∫cos(x)dx 下限0 上限2我知道求这种式子用matlab应该这么表达syms xint(cos(x),x,0,2)现在在式子前面乘以一个dx∫dxcos(x)dx 下限0 上限2请教高手用matlab该 / (cos x + 1 ) dx 求不定积分!∫cos^(-1)x dx ∫cos√x dx y=(1+x^2)arctan x 用MATLAB求(d^2*y)/dx^2 求∫1/(sin^4x+cos^4x)dx, 怎么用MATLAB求函数x*(1+cos(x))*cos(x)^2,x在[0,pi]上, 求1/(8*cos^2x+1)dx不定积分 求∫cos(ln(1/(1-x)))dx 求不定积分∫[1/(sin^2 cos^2(x)]dx 求不定积分∫(1+sinx) / cos^2 x dx 求∫cos（3x+1）dx. 求不定积分∫cos根号下x+1dx 求不定积分∫cos(2x+1)dx 求不定积分∫cos(2x-1)dx 求不定积分∫[1/sin^2cos^2 (x)]dx 求积分(cos^2x/(1+cosx))dx 求∫[0-->π](1-cos³x ）dx