解放程组2x-y=7,5x+3y+2z=2,3x-4z=4
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解放程组2x-y=7,5x+3y+2z=2,3x-4z=4
解放程组2x-y=7,5x+3y+2z=2,3x-4z=4
解放程组2x-y=7,5x+3y+2z=2,3x-4z=4
2x-y=7……(1)
5x+3y+2z=2……(2)
3x-4z=4……(3)
把①代入②
5x+3(2x-7)+2z=2
11x+2z=23 (4)
(3)+(4)*2
3x-4z+22x+4z=4+46
25x=50
x=2
z=(3x-4)/4=1/2
y=2x-7=-3
解放程组2x-y=7,5x+3y+2z=2,3x-4z=4
解放程:(2X+3Y-Z-2)的绝对值+(3X+2Y-Z-2)的平方+根号(4X-5Y+6Z+17)=0
解放程x+y-z=4,2x-y+x=5,x-3y+x=-2 3x-2y=8,2y+3z=1,x+5z=73x-2y=8,2y+3z=1,x+5z=7 方程,过程, 跪求!
解放程组2X-3Y=X+2=3X+Y
x/2=y/3=z/5 x+3y-z/x-3y+z
若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z)
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
x+Y+Z=1 X+3Y+7Z=-1 X+5Y+8Z=2x+Y+Z=1X+3Y+7Z=-1X+5Y+8Z=2
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
3x-y=-7,y+2z=2,2x-2z=-5 求x,y,z
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x+y+z=0,3x-2y-2z=5,y-z=2x-7
X-Y-Z=0 X+Y-3Z=4 2X-5Y+7Z=21
2x+5y+4z=6,3x+y-7z=-4,x+y-z=?
3x+7y+4z=35,x+5y+2z=40,x+y+z=( )
{x+y+z=1 {x+3y+7z=-1 {x+5y+8z=2