F-(M+m)g=(M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星,怎么得出!F= 〔2(m+M)〕/MF-(M+m)g=(M+m)a ···········
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F-(M+m)g=(M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星,怎么得出!F= 〔2(m+M)〕/MF-(M+m)g=(M+m)a ···········
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2(m+M)〕/M
F-(M+m)g=(M+m)a ····················☆
2f-Mg=Ma·····································★
联立上面两个星星,怎么得出!
F= 〔2f(m+M)〕/M
F-(M+m)g=(M+m)a ····················☆2f-Mg=Ma·····································★联立上面两个星星,怎么得出!F= 〔2(m+M)〕/MF-(M+m)g=(M+m)a ···········
(1)得F=(M+m)(g+a)
(2)得2f=M(g+a) (g+a)=2f/M
代入得
F=2f(M+m)/M
整体隔离法,第一个式子是整体分析,第二个式子隔离分析一个
F-(M+m)g=(M+m)a ····················☆
F=(M+m)(g+a)
2F-Mg=Ma·····································★
2F=M(g+a)
??题目抄错了?没错!请采纳好评
F-(M+m)g=(M+m)a ····················☆
F...
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F-(M+m)g=(M+m)a ····················☆
F=(M+m)(g+a)
2F-Mg=Ma·····································★
2F=M(g+a)
??题目抄错了?
收起
怎么有两个不一样F和f
观察有一个参数a 将a挪到一边 缺一个式子吧
很明显不能得出
f没法消掉。