已知数列{an}满足a1=0,a(n+1)=an+2n,那么a2005的值是?
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已知数列{an}满足a1=0,a(n+1)=an+2n,那么a2005的值是?
已知数列{an}满足a1=0,a(n+1)=an+2n,那么a2005的值是?
已知数列{an}满足a1=0,a(n+1)=an+2n,那么a2005的值是?
a(n+1)=an+2n
a(n+1)-an=2n
a2-a1=2*1
a3-a2=2*2
a4-a3=2*3
;
an-a(n-1)=2*(n-1)
上式迭加
an-a1=2(n-1)[1+(n-1)]/2=n(n-1)
an=n(n-1)
a2005=2005*2004=4018020
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