(7+m)(7+m)(7-m)求极值.三项基本不等式原理
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/18 02:38:36
(7+m)(7+m)(7-m)求极值.三项基本不等式原理
(7+m)(7+m)(7-m)求极值.三项基本不等式原理
(7+m)(7+m)(7-m)求极值.三项基本不等式原理
∵(7+m)(7+m)(7-m)=(7+m)(7+m)(14-2m)/2
而(7+m)(7+m)(14-2m)≤[(7+m+7+m+14-2m)/3]^3=(28/3)^3
∴(7+m)(7+m)(7-m)的最大值为1/2*(28/3)^3,取等条件为:7+m=14-2m,即:m=7/3
(7+m)(7+m)(7-m)求极值.三项基本不等式原理
m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m求m的值
如果m-3n+4=0,求:(m-3n)的二次方+7m-3(2m的三次方n-1)+3(m的三次方+如果m-3n+4=0,求:(m-3n)的二次方+7m-3(2m的三次方n-1)+3(m的三次方+2m的三次方n-m的二次方n+n)-m-10m的三次方的值.
m-2m-3m+4m-5m-6m+7m.2004m=?
m^2+3m-2,求3m^3+7m^2-12m+2014
如果m-3n+4=0,求(m-3n)的平方+7m的3次方-3(2m的三次方n-m的平方n-1)+3(m的三次方+2m的三次方n-m的平方n+n)-m-10m的三次方的值
如果A(1,2),B(3,m),C(7,m+2)三点共线,求实数m的值
计算(m+3m+5m+7m+.+2009m)-(2m+4m+6m+.+2008m)
计算(m+3m+5m+7m+.+2013m)-(2m+4m+6m+.+2012m)
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
已知m>4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3|
(m+3m+5m+7m+.+2011m)-(2m+4m+6m+.+2010m) 要说理由!
7m-0.9m+m=
计算:m-2m-3m+4m-5m-6m+7m-8m-9m+...+2002m-2003m-2004m
m-2m-3m+4m-5m-6m+7m-8m-9m+.+2002m-2003m-2004m
三点A(1,1),B(2,m),C(-m,-7)共线,求m的值三点A(1,1)、B(2,m)、C(-m,-7)共线,求m的值
已知9^(m+3)×27^(m+1)÷3^(4m+7)=81 求m
已知m^2-7m+1=0,求m^2+1/m^2的值