作业帮计算：(x-y+z)(-x+y+z)
来源：学生作业帮助网 编辑：作业帮 时间：2024/10/31 15:58:21
计算：(x-y+z)(-x+y+z)
计算：(x-y+z)(-x+y+z)
计算：(x-y+z)(-x+y+z)
(x-y+z)(-x+y+z)
=[z+(x-y)][z-(x-y)]
=z^2-(x-y)^2
=z^2-(x^2-2xy+y^2)
=z^2-x^2+2xy-y^2
原式＝[z＋（x－y）][z－（x－y）]
＝z² －（x－y）²
＝z²－x²－y²＋2xy
(x-y+z)(-x+y+z) =- (x-y+z)(x-y-z) =- [(x-y)^2]-z^2
这是一个化简题
先把负号提出来
原式可以化为
[z+(x-y)][z-(x-y)]
然后展开
z^2-(x-y)^2
最后
z^2-x^2+2xy-y^2
明白了吗？
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