Please help me.做以上题目.

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Please help me.做以上题目.
Please help me.做以上题目.
 

Please help me.做以上题目.
2;一般方程为2x-y+3=0
3;方程可写为3x+y=-3故在y轴上的截距为3
4;直线ax+by+c=0的方向向量为（b,-a）此题中为（-2,-3）法向量为（a,b）此题中为（3,-2）
5;斜率为-a/b,故为-3
画图暂时不方便传,不好意思~

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