我想问问怎么把x^2+y^2-4x+2y-4=0,化简成这个式子:(x-2)^2+(y+1)^2=9的,

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我想问问怎么把x^2+y^2-4x+2y-4=0,化简成这个式子:(x-2)^2+(y+1)^2=9的,
我想问问怎么把x^2+y^2-4x+2y-4=0,化简成这个式子:(x-2)^2+(y+1)^2=9的,

我想问问怎么把x^2+y^2-4x+2y-4=0,化简成这个式子:(x-2)^2+(y+1)^2=9的,
x^2+y^2-4x+2y-4=0
x^2+y^2-4x+2y=4
x^2-4x+y^2+2y=4
x^2-4x+4-4+y^2+2y+1-1=4
(x^2-4x+4)-4+(y^2+2y+1)-1=4
(x^2-4x+4)+(y^2+2y+1)=4+4+1
:(x-2)^2+(y+1)^2=9

x^2+y^2-4x+2y-4=0
x^2-4x+4-4+y^2+2y+1-1-4=0
(x-2)^2-4+(y+1)^2-1-4=0
(x-2)^2+(y+1)^2=9

x²+y²-4x+2y-4=0
x²-4x+4+y²+2y+1-9=0
(x-2)²+(y+1)²=9

x^2+y^2-4x+2y-4=0
(x^2-4x+4)+(y^2+2y+1)-4-5=0
(x-2)^2+(y+1)^2=9

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