#includevoid put(int ar[][5],int n);int main(void){int zhou[3][5]={{1,2,3,4,5},{2,3,4,5,6},{3,4,5,6,7}};put(zhou,5);return 0;}void put(int ar[][5],int n){int r,c;for(r=0;r

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#includevoid put(int ar[][5],int n);int main(void){int zhou[3][5]={{1,2,3,4,5},{2,3,4,5,6},{3,4,5,6,7}};put(zhou,5);return 0;}void put(int ar[][5],int n){int r,c;for(r=0;r
#include
void put(int ar[][5],int n);
int main(void)
{
int zhou[3][5]={
{1,2,3,4,5},
{2,3,4,5,6},
{3,4,5,6,7}
};
put(zhou,5);
return 0;
}
void put(int ar[][5],int n)
{
int r,c;
for(r=0;r

#includevoid put(int ar[][5],int n);int main(void){int zhou[3][5]={{1,2,3,4,5},{2,3,4,5,6},{3,4,5,6,7}};put(zhou,5);return 0;}void put(int ar[][5],int n){int r,c;for(r=0;r
#include
void put(int ar[][5],int n);
int main(void)
{
int zhou[3][5]={
{1,2,3,4,5},
{2,3,4,5,6},
{3,4,5,6,7}
};
put(zhou,3);
return 0;
}
void put(int ar[][5],int n)
{
int r,c;
for(r=0;r

#includevoid put(int ar[][5],int n);int main(void){int zhou[3][5]={{1,2,3,4,5},{2,3,4,5,6},{3,4,5,6,7}};put(zhou,5);return 0;}void put(int ar[][5],int n){int r,c;for(r=0;r c++求2+22+222+2222+22222.#includevoid main(){int sum=0;int a=2;int n;coutn;for(int i=1;i 以下程序的运行结果是输出如下图形** * ** * * * ** * * * * * ** * * * * * * * *#includevoid a(int i){int j,k;for(j=0;j #includevoid numplus();void mumminus();void main (){mumplus();mumminus();}void numplus(){for (int i=0;i 输出符合条件的xyz#includevoid main(){int x,y,z;for(x=1;x 简单C++,给每行注释吧.#includevoid main(){ int i=1,j; for(;i empty character constant什么意思#includevoid main (){ int i;float score[10];cout Fibonacci数列函数的定义出错问题...#define M 4 #define N 5#includevoid main(){int i;int fibonacci(int n){if(n C++程序解释请详细说明含义好吗?#include#includevoid main(){int* p;p=new int [8];for(int i=0;i C++求两个集合的交集#includevoid main(){ int a[5],b[5],c[5]; int i,j,k; int *p1,*p2,*p3; cout 我想知道到底错在哪?#includevoid a(int []);void main(){int buu[5];int i;for(i=0;i C语言正数相加变负数#includevoid main(){ int i,sum=0;for(i=200;i #includevoid main(){int *p1,*p2,a[5]={1,3,5,7,9};for(p1=a;p1 #includevoid fun(int x){ if(x/2>0) fun(x/2);printf(%d,x);}main(){fun(3); printf( );} 求2到999之间同构数和 #includevoid main(){int i,square;for(i=2;i 通过使用双重for循环语句,打印下列图形:#includevoid main(){int i,j,k;for(i=1;i 下面的程序错在哪里并改正#includevoid main(){ int a=0,b,c;while(a 求下列程序输出结果#includevoid main(){int a=3;printf(%d ,(a+=a-=a*a));}