(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
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(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)
=cosπ/12*cosπ/12-sinπ/12*sinπ/12
=cos2*π/12
=cosπ/6
=√3/2
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)=
(sinπ/24)(cosπ/24)(cosπ/12)
(sinπ/24)(cosπ/24)(cosπ/12)
sinπ/12*cosπ/12=?
求值:sin(π/12)+cos(π/12)
sin(π/12)-cos(π/12)=
cos*π/12—sin*π/12
cosπ/12乘以sinπ/12
计算cosπ/12*sinπ/12
已知α=7/12π,那么cosα√(1-sinα)/(1+sinα)+sinα√(1-cosα)/(1-cosα)=
-(cos^2π/12-sin^2π/12)为什么等于-(cosα+π/12)
(cosπ/12-sinπ/12)*(COSπ/12+sinπ/12)等于
(cosπ/12 -sinπ/12)(cosπ/12 +sinπ/12)等于
(cosπ/12-sinπ/12)(cosπ/12+sinπ/12)的值为
(sinπ/12+cosπ/12)(sinπ/12-cosπ/12)=
cos^2π/12-sin^2π/12等于
sin(π/12)cos(π/12)的值
求sin π/12-(根号3)cos π/12